Slip 11_1: Accept n values in array from user. Accept a value x from user and use sentinel linear search algorithm to check whether the number is present in the array or not and output the position if the number is present

-

 Solution :

#include<stdio.h>

void sentinelsearch(int a[10],int n,int sr)

{ int i,cnt=0;

 a[n]=sr;

 while(sr!=a[i])

 { i++;

 }

 if(i<n)

 printf("Element is found at %d position ",i);

 else

 printf("element is not found ");

}

main()

{

 int n,i,sr,a[10];

 printf("enter how many values");

 scanf("%d",&n);

 for(i=0;i<n;i++)

 {

 printf("enter values");

 scanf("%d",&a[i]);

 }

 printf("\n enter search element");

 scanf("%d",&sr);

 sentinelsearch(a,n,sr);

}


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